首页 > 医卫类 > 医技职称 > 放射医学(士) > 相关专业知识 > X 线最强波长 ( λmax) 与最短波长 (λmin) 的关系是

X 线最强波长 ( λmax) 与最短波长 (λmin) 的关系是

A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
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正确答案: C
答案分析:
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A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
A.λ max =0 .5λ min
B.λ max = λ min
C.λ max =1 .5λ min
D.Amax=2Amin
E.Amax=2.5Amin
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