检索选修四门以上课程的学生总成绩(不统计不及格的课程 ),并要求按总成绩的降序捧列出来。正确的 SElECT 语句是
A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
C.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVINC COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESC
D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
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正确答案: B 答案分析:无
包含此试题的试卷:
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A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
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C.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVINC COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESC
D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
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B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
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D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
C.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVINC COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESC
D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
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D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
C.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVINC COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESC
D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
C.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVINC COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESC
D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
C.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVINC COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESC
D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
C.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVINC COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESC
D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4
A.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 CROUP BY S# ORDER BY 2 DESC HAVING COUNT(*)>=4
B.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 GROUP BY S# HAVING COUNT(*)>=4 ORDER BY 2 DESC
C.SELECT S#,SUM(GRADE)FROM SC WHERE GRADE>=60 HAVINC COUNT(*)>=4 GROUP BY S# ORDER BY 2 DESC
D.SELECT S#,SUM(GRADE) FROM SC WHERE GRADE>=60 ORDER BY2 DESC GROUP BY S# HAVING COUNT(*)>=4