在 Excel 2003 中，要产生 [300，550]间的随机整数，下面【 】公式是正确的。
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
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正确答案： B 答案分析：无
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A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
A.=RAND()*250+300
B.=int(rand()*251)+300
C.=int(rand()*250)+301
D.=int(rand()*250)+300
