以下程序输出到文件 text.csv 里的结果是:
fo = open("text.csv",'w')
x = [90,87,93]
z = []
for y in x:
z.append(str(y))
fo.write(",".join(z))
fo.close()
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
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正确答案: B 答案分析:无
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A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’
A.[90,87,93]
B.90,87,93
C.‘[90,87,93] ’
D.‘90,87,93 ’