花样滑冰运动员绕通过自身的竖直轴转动,开始时两臂合拢,转动惯量为J0,角速度为ω0;当其两臂伸开后,角速度变为5ω0/6,则其转动惯量变为(忽略阻力)
A.[img src="https://img.haodaxue.net/uploadimg/ico/2020/0619/1592536490128951.png" />
B.[img src="https://img.haodaxue.net/uploadimg/ico/2020/0619/1592536505228179.png" />
C.[img src="https://img.haodaxue.net/uploadimg/ico/2020/0619/1592536537577930.png" />
D.[img src="https://img.haodaxue.net/uploadimg/ico/2020/0619/1592536551948076.png" />
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正确答案: C 答案分析:无
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