使物体脱离星球的引力束缚，不再绕星球运行， 从星球表面发射所需的最小速度称为第二宇宙速度，星球的第二宇宙速度V2与第一宇宙速度 V 1的关系是[img src="https://img.haodaxue.net/uploadimg/image/20200512/20200512164638_19600.png" alt="" />已知某星球的半径为 r，它表面的重力加速度为地球表面重力加速度g的16。不计其他星球的影响，则该星球的第二宇宙速度为（）
A.[img src="http://img.haodaxue.net/uploadimg/ico/2020/0512/1589273246628367.png" />
B.[img src="http://img.haodaxue.net/uploadimg/ico/2020/0512/1589273262108177.png" />
C.[img src="http://img.haodaxue.net/uploadimg/ico/2020/0512/1589273278678434.png" />
D.[img src="http://img.haodaxue.net/uploadimg/ico/2020/0512/1589273297497059.png" />
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正确答案： B 答案分析：无
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